Q.
In the Young's double-slit experiment, the intensity of light at a point on the screen where the path difference is λ is K, (λ being the wave length of light used). The intensity at a point where the path difference is λ/4 will be :
A) K
B) K/4
C) K/2
D) Zero
Explanation
[Solution] $I = K\cos^2(\phi/2)$; path difference λ/4 gives φ = π/2, so I = K cos²45° = K/2. Answer (3).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.