Q. When 22.4 litres of $H_2$(g) is mixed with 11.2 litres of $Cl_2$(g), each at S.T.P, the moles of HCl(g) formed is equal to :
A) 1 mol of HCl(g)
B) 2 mol of HCl(g)
C) 0.5 mol of HCl(g)
D) 1.5 mol of HCl(g)
Explanation
[Solution] $H_2 + Cl_2 \rightarrow 2HCl$; $Cl_2$ (0.5 mol) is limiting, giving 1 mol HCl. Answer (1).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.