Q. Using the Gibbs energy change, $\Delta G^o$ = +63.3 kJ, for the following reaction, $Ag_2CO_3(s) \rightleftharpoons 2Ag^+(aq) + CO_3^{2-}(aq)$, the $K_{sp}$ of $Ag_2CO_3$(s) in water at 25°C is : (R = 8.314 $JK^{-1}mol^{-1}$)
A) $3.2 \times 10^{-26}$
B) $8.0 \times 10^{-12}$
C) $2.9 \times 10^{-3}$
D) $7.9 \times 10^{-2}$
Explanation
[Solution] $\log K_{sp} = -\frac{63300}{2.303 \times 8.314 \times 298} = -11.09$, so $K_{sp} = 8.0 \times 10^{-12}$. Answer (2).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.