Q. For the reaction : $X_2O_4(l) \rightarrow 2XO_2(g)$, ΔU = 2.1 kcal, ΔS = 20 cal $K^{-1}$ at 300 K. Hence, ΔG is :
A) 2.7 kcal
B) –2.7 kcal
C) 9.3 kcal
D) –9.3 kcal
Explanation
[Solution] ΔH = ΔU + Δn RT = 2.1 + 2 × 0.002 × 300 = 3.3 kcal; ΔG = 3.3 − 300 × 0.020 = −2.7 kcal. Answer (2).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.