For a given exothermic reaction, $K_p$ and $K'_p$ are the equilibrium constants at temperatures $T_1$ and $T_2$, respectively. Assuming that heat of reaction is constant in temperature range between $T_1$ and $T_2$, it is readily observed that :

Question

Dr. Abubacker · Accepted Answer

[Solution] For an exothermic reaction K decreases as temperature rises; taking $T_2 > T_1$, $K_p > K'_p$. (The key in the PDF gives (3), which is incorrect; standard solutions give (1).) Answer (1).

Q. For a given exothermic reaction, $K_p$ and $K'_p$ are the equilibrium constants at temperatures $T_1$ and $T_2$, respectively. Assuming that heat of reaction is constant in temperature range between $T_1$ and $T_2$, it is readily observed that :

Explanation

Reviewed by Dr. Abubacker

Want to attempt the full paper?