Q. In acidic medium, $H_2O_2$ changes $Cr_2O_7^{2-}$ to $CrO_5$ which has two (–O–O–) bonds. Oxidation state of Cr in $CrO_5$ is :
A) +5
B) +3
C) +6
D) –10
Explanation
[Solution] $CrO_5$ has one oxide (−2) and two peroxide groups (4 × −1): x − 2 − 4 = 0, x = +6. Answer (3).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.