In an adiabatic expansion, the temperature of one mole of an ideal monatomic gas (γ = 5/3) decreases from 60 K to 50 K. The work done by the gas in the process is: (Take the universal gas constant as R = 8.3 J mol⁻¹ K⁻¹)

Question

Dr. Abubacker · Accepted Answer

[Solution from source] For an adiabatic process $W=nR(T_1-T_2)/(\gamma-1)=8.3	imes10/(2/3)=124.5$ J, equal to the fall in internal energy $\frac32R\Delta T$. Answer (4).

Q. In an adiabatic expansion, the temperature of one mole of an ideal monatomic gas (γ = 5/3) decreases from 60 K to 50 K. The work done by the gas in the process is: (Take the universal gas constant as R = 8.3 J mol⁻¹ K⁻¹)

Explanation

Reviewed by Dr. Abubacker

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