Consider a particle moving along a straight line, whose position as a function of time is given by $s(t)=\alpha t^2-\beta t+\gamma$, where α = 1 m s⁻², β = 6 m s⁻¹ and γ = 5 m. The average speed of the particle, in m s⁻¹ from t = 0 to t = 6 s is:

Question

Dr. Abubacker · Accepted Answer

[Solution from source] $s=t^2-6t+5$ and $v=2t-6$, which reverses at t = 3 s. s(0) = 5 m, s(3) = −4 m, s(6) = 5 m, so distance = 9 + 9 = 18 m and average speed = 18/6 = 3 m s⁻¹. Answer (4).

Q. Consider a particle moving along a straight line, whose position as a function of time is given by $s(t)=\alpha t^2-\beta t+\gamma$, where α = 1 m s⁻², β = 6 m s⁻¹ and γ = 5 m. The average speed of the particle, in m s⁻¹ from t = 0 to t = 6 s is:

Explanation

Reviewed by Dr. Abubacker

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