The mean free path of molecules in an ideal gas A is half that of another ideal gas B. The diameter of the spherical molecules of gas A is twice the diameter of the molecules of B. If number densities of the gases A and B are $n_A$ and $n_B$, respectively, the correct option is:

Question

Dr. Abubacker · Accepted Answer

[Solution from source] $\lambda=1/(\sqrt2\pi d^2n)$, so $\lambda_A/\lambda_B=n_B/(4n_A)$. Setting this equal to 1/2 gives $n_A=n_B/2$. Answer (1).

Q. The mean free path of molecules in an ideal gas A is half that of another ideal gas B. The diameter of the spherical molecules of gas A is twice the diameter of the molecules of B. If number densities of the gases A and B are $n_A$ and $n_B$, respectively, the correct option is:

Explanation

Reviewed by Dr. Abubacker

Want to attempt the full paper?