Q.
A ray of light with wavelength λ is incident on three different photoelectric cells namely 1, 2 and 3. The threshold wavelength of these photoelectric cells are λ₁, λ₂, and λ₃, respectively and the magnitude of stopping potentials of these cells are V₁, V₂ and V₃, respectively. The relation between λ and threshold wavelengths are λ₁ < λ, λ₂ > λ and λ₃ ≫ λ. The correct option is:
A) V₁ < V₂, V₃ = 0
B) V₁ = 0, V₂ < V₃
C) V₁ = 0, V₂ > V₃
D) V₁ > V₂, V₃ = 0
Explanation
[Solution from source] Emission occurs only if λ is shorter than the threshold wavelength. For cell 1 (λ₁ < λ) there is no emission, so V₁ = 0. $eV=hc/\lambda-hc/\lambda_0$ grows as the threshold λ₀ increases, so V₃ (λ₃ ≫ λ) exceeds V₂. Answer (2).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.