Q. In an acidic medium, 10 mL of 0.25 M oxalic acid is titrated with KMnO₄ solution. If the volume of KMnO₄ solution required to reach end point is 10 mL, the strength of the KMnO₄ solution is
A) 0.15 M
B) 0.10 M
C) 0.20 M
D) 0.25 M
Explanation
[Solution from source] 2MnO₄⁻ + 5C₂O₄²⁻ + 16H⁺ → 2Mn²⁺ + 10CO₂ + 8H₂O. Oxalic acid = 2.5 mmol, so MnO₄⁻ needed = 2.5 × 2/5 = 1.0 mmol in 10 mL, i.e. 0.10 M. Answer (2).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.