Q. The correct order of solubility of the given salts in water at 298 K is [table] Salt | Ksp at 298 K ; AgBr | 5.0 × 10⁻¹³ ; Zn(OH)₂ | 1.0 × 10⁻¹⁵ ; Hg₂Cl₂ | 1.3 × 10⁻¹⁸ [/table]
A) Zn(OH)₂ > AgBr > Hg₂Cl₂
B) Hg₂Cl₂ > Zn(OH)₂ > AgBr
C) AgBr > Zn(OH)₂ > Hg₂Cl₂
D) Hg₂Cl₂ > AgBr > Zn(OH)₂
Explanation
[Solution from source] AgBr: s = √(5.0 × 10⁻¹³) ≈ 7.1 × 10⁻⁷ M. Zn(OH)₂: 4s³ = 1.0 × 10⁻¹⁵, s ≈ 6.3 × 10⁻⁶ M. Hg₂Cl₂: 4s³ = 1.3 × 10⁻¹⁸, s ≈ 6.9 × 10⁻⁷ M. So Zn(OH)₂ > AgBr > Hg₂Cl₂. Answer (1).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.