Q. The velocity of a projectile at the initial point A is (2î + 3ĵ) m/s. Its velocity (in m/s) at point B (the point where it returns to the same horizontal level as A) is

A) −2î − 3ĵ
B) −2î + 3ĵ
C) 2î − 3ĵ
D) 2î + 3ĵ
Explanation

[Solution from source] With no horizontal force the horizontal component stays 2î, while at the same level the vertical component has the same size but reverses, becoming −3ĵ. So the velocity at B is 2î − 3ĵ; reversing both components would wrongly reverse the horizontal motion too. Answer (3).

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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