Q. A uniform force of (3î + ĵ) newton acts on a particle of mass 2 kg. Hence the particle is displaced from position (2î + k̂) metre to position (4î + 3ĵ − k̂) metre. The work done by the force on the particle is

A) 9 J
B) 6 J
C) 13 J
D) 15 J
Explanation

[Solution from source] Displacement d = (4î + 3ĵ − k̂) − (2î + k̂) = 2î + 3ĵ − 2k̂. W = F·d = 3 × 2 + 1 × 3 + 0 × (−2) = 9 J. The mass of the particle is not needed for the work done by a given force. Answer (1).

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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