Q.
A uniform force of (3î + ĵ) newton acts on a particle of mass 2 kg. Hence the particle is displaced from position (2î + k̂) metre to position (4î + 3ĵ − k̂) metre. The work done by the force on the particle is
A) 9 J
B) 6 J
C) 13 J
D) 15 J
Explanation
[Solution from source] Displacement d = (4î + 3ĵ − k̂) − (2î + k̂) = 2î + 3ĵ − 2k̂. W = F·d = 3 × 2 + 1 × 3 + 0 × (−2) = 9 J. The mass of the particle is not needed for the work done by a given force. Answer (1).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.