[Solution from source] Initial momentum is zero. The first two momenta are 1 × 12 = 12 and 2 × 8 = 16 kg m s⁻¹ at right angles, giving a resultant √(12² + 16²) = 20 kg m s⁻¹. The third part must carry 20 kg m s⁻¹ in the opposite direction, so m = 20/4 = 5 kg. Answer (2).