A small object of uniform density rolls up a curved surface with an initial velocity v. It reaches up to a maximum height of 3v²/(4g) with respect to the initial position. The object is

Question

Dr. Abubacker · Accepted Answer

[Solution from source] Rolling KE = (1/2)mv²(1 + k²/R²) is converted to mgh = mg × 3v²/(4g) = (3/4)mv². So 1 + k²/R² = 3/2, k²/R² = 1/2, which is the value for a disc. A solid sphere (k²/R² = 2/5) or a ring (k²/R² = 1) would rise to different heights. Answer (4).

Q. A small object of uniform density rolls up a curved surface with an initial velocity v. It reaches up to a maximum height of 3v²/(4g) with respect to the initial position. The object is

Explanation

Reviewed by Dr. Abubacker

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