Q.
In a common emitter (CE) amplifier having a voltage gain G, the transistor used has transconductance 0.03 mho and current gain 25. If the above transistor is replaced with another one with transconductance 0.02 mho and current gain 20, the voltage gain will be
A) (2/3)G
B) 1.5G
C) (1/3)G
D) (5/4)G
Explanation
[Solution from source] Voltage gain of a CE amplifier Av = gm × RL. With the same load resistance, G′/G = 0.02/0.03, so G′ = (2/3)G. The current gain does not enter this relation, so using 20/25 gives a wrong answer. Answer (1).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.