Q. 6.02 × 10²⁰ molecules of urea are present in 100 mL of its solution. The concentration of solution is
A) 0.02 M
B) 0.01 M
C) 0.001 M
D) 0.1 M
Explanation
[Solution from source] Moles of urea = 6.02 × 10²⁰/6.02 × 10²³ = 1 × 10⁻³ mol in 100 mL = 0.1 L. Molarity = 10⁻³/0.1 = 0.01 M. 0.001 M forgets to convert 100 mL into litres. Answer (2).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.