Q. Given that the equilibrium constant for the reaction 2SO₂(g) + O₂(g) ⇌ 2SO₃(g) has a value of 278 at a particular temperature. What is the value of the equilibrium constant for the following reaction at the same temperature? SO₃(g) ⇌ SO₂(g) + (1/2)O₂(g)
A) 1.8 × 10⁻³
B) 3.6 × 10⁻³
C) 6.0 × 10⁻²
D) 1.3 × 10⁻⁵
Explanation
[Solution from source] The required reaction is the given one reversed and halved, so K′ = (1/278)^(1/2) = 1/16.7 ≈ 6.0 × 10⁻². Reversing without taking the square root gives 3.6 × 10⁻³. Answer (3).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.