Q. The orbital angular momentum of a p-electron is given as :
A) h/(√2 π)
B) √3 h/(2π)
C) √(3/2) h/π
D) √6 h/(2π)
Explanation
[Solution from source] Orbital angular momentum = √(l(l + 1))·h/2π. For a p-electron l = 1, giving √2·h/2π = h/(√2 π). √6·h/2π would be for a d-electron (l = 2). Answer (1).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.