Q. A solid cylinder of mass 3 kg is rolling on a horizontal surface with velocity 4 m s⁻¹. It collides with a horizontal spring of force constant 200 N m⁻¹. The maximum compression produced in the spring will be
A) 0.2 m
B) 0.5 m
C) 0.6 m
D) 0.7 m
Explanation
[Solution from source] A rolling solid cylinder has KE = ½mv² + ½(½mR²)(v/R)² = ¾mv² = ¾ × 3 × 16 = 36 J. Setting ½kx² = 36 gives x² = 72/200 = 0.36, so x = 0.6 m. Ignoring rotational KE gives 24 J and x ≈ 0.49 m, which leads to the 0.5 m trap. Answer (3).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.