Q. The horizontal range and the maximum height of a projectile are equal. The angle of projection of the projectile is
A) θ = 45°
B) θ = tan⁻¹(1/4)
C) θ = tan⁻¹(4)
D) θ = tan⁻¹(2)
Explanation
[Solution from source] Range R = u² sin 2θ/g = 2u² sin θ cos θ/g and maximum height H = u² sin²θ/(2g). Setting R = H gives 2 cos θ = sin θ/2, i.e. tan θ = 4, so θ = tan⁻¹ 4. An angle of 45° gives maximum range, not R = H. Answer (3).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.