Q. If the nuclear radius of ²⁷Al is 3.6 fermi, the approximate nuclear radius of ⁶⁴Cu in fermi is
A) 3.6
B) 2.4
C) 1.2
D) 4.8
Explanation
[Solution from source] Nuclear radius R ∝ A^(1/3), so R_Cu = 3.6 × (64/27)^(1/3) = 3.6 × 4/3 = 4.8 fermi. A heavier nucleus must have a larger radius, which rules out the smaller values. Answer (4).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.