[Solution from source] The coils give fields μ₀I/(2R) and μ₀(2I)/(2R) = μ₀I/R at the centre, and these are perpendicular because the coil planes are perpendicular. Resultant B = √[(μ₀I/2R)² + (μ₀I/R)²] = √5 μ₀I/(2R). Simply adding them (3μ₀I/2R) ignores that the fields are at right angles. Answer (2).