Q. The height at which the weight of a body becomes 1/16th of its weight on the surface of earth (radius R) is
A) 4R
B) 5R
C) 15R
D) 3R
Explanation
[Solution from source] g_h = g/(1 + h/R)². For g_h = g/16, 1 + h/R = 4, so h = 3R. 4R is the distance from the centre of the earth, not the height above the surface. Answer (4).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.