Q. A car of mass 1000 kg negotiates a banked curve of radius 90 m on a frictionless road. If the banking angle is 45°, the speed of the car is
A) 10 m s⁻¹
B) 20 m s⁻¹
C) 30 m s⁻¹
D) 5 m s⁻¹
Explanation
[Solution from source] On a frictionless banked road, tan θ = v²/(rg). With θ = 45°, v = √(rg) = √(90 × 10) = 30 m s⁻¹ (g = 10 m s⁻²). The mass of the car does not enter the result. Answer (3).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.