Q. The enthalpy of fusion of water is 1.435 kcal/mol. The molar entropy change for the melting of ice at 0°C is
A) 0.526 cal/(mol K)
B) 10.52 cal/(mol K)
C) 21.04 cal/(mol K)
D) 5.260 cal/(mol K)
Explanation
[Solution from source] ΔS_fus = ΔH_fus/T = 1435 cal mol⁻¹/273 K = 5.26 cal mol⁻¹ K⁻¹. 0.526 results from a misplaced decimal and 10.52 from doubling. Answer (4).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.