Q. In Freundlich Adsorption isotherm, the value of 1/n is:
A) 1 in case of chemisorption
B) between 0 and 1 in all cases
C) between 2 and 4 in all cases
D) 1 in case of physical adsorption
Explanation
[Solution from source] In the Freundlich isotherm x/m = kp^(1/n), the exponent 1/n lies between 0 and 1, reflecting that adsorption rises less than proportionally with pressure. 1/n = 1 is only the limiting low-pressure case and is not specific to either physisorption or chemisorption. Answer (2).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.