Q. Bond order of 1.5 is shown by:
A) O₂
B) O₂⁺
C) O₂⁻
D) O₂²⁻
Explanation
[Solution from source] By MO theory, O₂⁻ has 10 bonding and 7 antibonding electrons (valence), bond order = (10 − 7)/2 = 1.5. O₂ is 2, O₂⁺ is 2.5 and O₂²⁻ is 1. Answer (3).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.