Q. In the following sequence of reactions CH₃–Br —(KCN)→ A —(H₃O⁺)→ B —(LiAlH₄, ether)→ C, the end product (C) is
A) Ethyl alcohol
B) Acetone
C) Methane
D) Acetaldehyde
Explanation
[Solution from source] CH₃Br + KCN gives CH₃CN; acid hydrolysis converts it to CH₃COOH; LiAlH₄ then reduces the acid to CH₃CH₂OH, ethyl alcohol, as the end product. Acetaldehyde is not isolated because LiAlH₄ reduces carboxylic acids all the way to primary alcohols. Answer (1).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.