Q. Two particles are oscillating along two close parallel straight lines side by side, with the same frequency and amplitudes. They pass each other, moving in opposite directions when their displacement is half of the amplitude. The mean positions of the two particles lie on a straight line perpendicular to the paths of the two particles. The phase difference is
A) π
B) π/6
C) 0
D) 2π/3
Explanation
[Solution from source] x = A sin φ = A/2 gives φ = π/6 for one particle and 5π/6 for the other, since they move in opposite directions at that displacement. Phase difference = 5π/6 − π/6 = 2π/3. Zero would mean they move together, and π would mean they cross only at the mean position. Answer (4).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.