Two identical piano wires, kept under the same tension T, have a fundamental frequency of 600 Hz. The fractional increase in the tension of one of the wires which will lead to occurrence of 6 beats/s when both the wires oscillate together would be

Question

Dr. Abubacker · Accepted Answer

[Solution from source] f ∝ √T, so Δf/f = ½ ΔT/T. Six beats means Δf = 6 Hz, so 6/600 = ½ ΔT/T and ΔT/T = 0.02. Forgetting the square-root dependence gives 0.01. Answer (3).

Q. Two identical piano wires, kept under the same tension T, have a fundamental frequency of 600 Hz. The fractional increase in the tension of one of the wires which will lead to occurrence of 6 beats/s when both the wires oscillate together would be

Explanation

Reviewed by Dr. Abubacker

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