The half life of a substance in a certain enzyme-catalysed reaction is 138 s. The time required for the concentration of the substance to fall from 1.28 mg L⁻¹ to 0.04 mg L⁻¹ is

Question

Dr. Abubacker · Accepted Answer

[Solution from source] A constant half-life means first-order kinetics. 1.28/0.04 = 32 = 2⁵, so five half-lives are needed: 5 × 138 = 690 s. 552 s corresponds to only four half-lives. Answer (1).

Q. The half life of a substance in a certain enzyme-catalysed reaction is 138 s. The time required for the concentration of the substance to fall from 1.28 mg L⁻¹ to 0.04 mg L⁻¹ is

Explanation

Reviewed by Dr. Abubacker

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