Q. A body of mass M hits normally a rigid wall with velocity V and bounces back with the same velocity. The impulse experienced by the body is
A) Zero
B) MV
C) 1.5 MV
D) 2 MV
Explanation
[Solution from source] Impulse equals change in momentum: taking the initial direction as positive, Δp = (−MV) − (MV) = −2MV, so its magnitude is 2MV. Zero would only be the change in speed, not in momentum. Answer (4).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.