Q. A charge Q is enclosed by a Gaussian spherical surface of radius R. If the radius is doubled, then the outward electric flux will
A) Be doubled
B) Increase four times
C) Be reduced to half
D) Remain the same
Explanation
[Solution from source] By Gauss's law, the total flux through any closed surface is q(enclosed)/ε₀. The enclosed charge is still Q when the radius doubles, so the flux remains the same; the field falls as 1/r² but the area grows as r². Answer (4).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.