A current carrying closed loop in the form of a right angle isosceles triangle ABC (right angle at B) is placed in a uniform magnetic field acting along AB. If the magnetic force on the arm BC is F⃗, the force on the arm AC is

Question

Dr. Abubacker · Accepted Answer

[Solution from source] The field is along AB, so the force on arm AB is zero. The net magnetic force on any closed current loop in a uniform field is zero, so F(BC) + F(AC) = 0 and the force on AC is −F⃗. A factor of √2 is the trap from the longer length of AC, but only the component of AC perpendicular to B (equal to BC) matters. Answer (3).

Q. A current carrying closed loop in the form of a right angle isosceles triangle ABC (right angle at B) is placed in a uniform magnetic field acting along AB. If the magnetic force on the arm BC is F⃗, the force on the arm AC is

Explanation

Reviewed by Dr. Abubacker

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