Q. In an ac circuit an alternating voltage e = 200√2 sin 100t volts is connected to a capacitor of capacity 1 µF. The r.m.s. value of the current in the circuit is
A) 20 mA
B) 10 mA
C) 100 mA
D) 200 mA
Explanation
[Solution from source] V(rms) = 200√2/√2 = 200 V and ω = 100 rad/s, so X_C = 1/(ωC) = 1/(100 × 10⁻⁶) = 10⁴ Ω. I(rms) = 200/10⁴ = 0.02 A = 20 mA. Using the peak voltage 200√2 V would give about 28 mA, which is not the rms value. Answer (1).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.