Q. Two waves are represented by the equations y₁ = a sin(ωt + kx + 0.57) m and y₂ = a cos(ωt + kx) m, where x is in metre and t in s. The phase difference between them is
A) 0.57 radian
B) 1.0 radian
C) 1.25 radian
D) 1.57 radian
Explanation
[Solution from source] Write y₂ = a cos(ωt + kx) = a sin(ωt + kx + π/2). The phase difference is π/2 − 0.57 = 1.57 − 0.57 = 1.0 radian. 1.57 rad would be the phase of the cosine wave alone, ignoring the 0.57 in the first wave. Answer (2).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.