Q. If the enthalpy change for the transition of liquid water to steam is 30 kJ mol⁻¹ at 27°C, the entropy change for the process would be
A) 100 J mol⁻¹ K⁻¹
B) 10 J mol⁻¹ K⁻¹
C) 1.0 J mol⁻¹ K⁻¹
D) 0.1 J mol⁻¹ K⁻¹
Explanation
[Solution from source] At the transition temperature ΔS = ΔH/T = 30000 J mol⁻¹/300 K = 100 J mol⁻¹ K⁻¹. Forgetting to convert kJ to J gives 0.1, the trap. Answer (1).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.