Q. The energies E₁ and E₂ of two radiations are 25 eV and 50 eV respectively. The relation between their wavelengths i.e. λ₁ and λ₂ will be
A) λ₁ = (1/2)λ₂
B) λ₁ = λ₂
C) λ₁ = 2λ₂
D) λ₁ = 4λ₂
Explanation
[Solution from source] E = hc/λ, so λ ∝ 1/E. E₂ is twice E₁, so λ₂ = λ₁/2, i.e. λ₁ = 2λ₂. The higher-energy radiation has the shorter wavelength, so λ₁ = λ₂/2 is the reverse. Answer (3).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.