[Solution from source] Ni²⁺ is d⁸; strong-field CN⁻ pairs all electrons and gives a dsp² square planar complex with no unpaired electrons, so [Ni(CN)₄]²⁻ is diamagnetic. [NiCl₄]²⁻ is tetrahedral sp³ with 2 unpaired electrons, [CoF₆]³⁻ has 4 and [CuCl₄]²⁻ (d⁹) has 1. Answer (3).