Q. What is the product obtained in the following reaction? C₆H₅NO₂ —(Zn, NH₄Cl)→ ?
A) C₆H₅NH₂ (aniline)
B) C₆H₅NHOH (N-phenylhydroxylamine)
C) C₆H₅–N=N–C₆H₅ (azobenzene)
D) C₆H₅–N(O⁻)=N⁺–C₆H₅ (azoxybenzene)
Explanation
[Solution from source] Nitrobenzene in neutral medium (Zn dust with NH₄Cl) is reduced only as far as N-phenylhydroxylamine, C₆H₅NHOH. Aniline forms in acidic medium (Sn/HCl or Fe/HCl), and azo/azoxy compounds in alkaline reductions. Answer (2).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.