Q. In a set of reactions m-bromobenzoic acid (A) gave a product D: A —(SOCl₂)→ B —(NH₃)→ C —(NaOH, Br₂)→ D Identify the product D.
A) 3-Bromobenzamide (m-Br–C₆H₄–CONH₂)
B) 3-Bromobenzenesulphonamide (m-Br–C₆H₄–SO₂NH₂)
C) 3-Aminobenzoic acid (m-H₂N–C₆H₄–COOH)
D) 3-Bromoaniline (m-Br–C₆H₄–NH₂)
Explanation
[Solution from source] SOCl₂ converts the acid to m-bromobenzoyl chloride, NH₃ converts it to m-bromobenzamide, and Br₂/NaOH (Hoffmann bromamide degradation) removes the carbonyl carbon to give m-bromoaniline. The amide is only the intermediate C, not the final product. Answer (4).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.