Q. In Dumas' method of estimation of nitrogen 0.35 g of an organic compound gave 55 mL of nitrogen collected at 300 K temperature and 715 mm pressure. The percentage composition of nitrogen in the compound would be (Aqueous tension at 300 K = 15 mm)

A) 14.45
B) 15.45
C) 16.45
D) 17.45
Explanation

[Solution from source] Pressure of dry N₂ = 715 − 15 = 700 mm. Volume at STP = 55 × (700/760) × (273/300) = 46.1 mL. Mass of N₂ = 28 × 46.1/22400 = 0.0576 g, so %N = 0.0576/0.35 × 100 ≈ 16.5 (16.45). Forgetting the aqueous tension correction gives a higher value. Answer (3).

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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