Q. Considering the state of hybridization of carbon atoms, find out the molecule among the following which is linear?
A) CH₃–CH₂–CH₂–CH₃
B) CH₃–CH=CH–CH₃
C) CH₃–C≡C–CH₃
D) CH₂=CH–CH₂–C≡CH
Explanation
[Solution from source] In CH₃–C≡C–CH₃ both triple-bonded carbons are sp hybridised (180°), so all four carbons lie on a straight line. Butane and but-2-ene contain sp³ or sp² carbons that bend the chain, and pent-1-en-4-yne has sp³ and sp² centres. Answer (3).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.