Q. The speed of a projectile at its maximum height is half of its initial speed. The angle of projection is
A) 60°
B) 15°
C) 30°
D) 45°
Explanation
[Solution from source] At the highest point only the horizontal component u cos θ remains. Setting u cos θ = u/2 gives cos θ = 1/2, so θ = 60°. An angle of 30° would leave a speed of (√3/2)u at the top. Answer (1).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.