Q. A monoatomic gas at pressure P₁ and volume V₁ is compressed adiabatically to 1/8th of its original volume. What is the final pressure of the gas?
A) 64 P₁
B) P₁
C) 16 P₁
D) 32 P₁
Explanation
[Solution from source] For an adiabatic process PV^γ is constant with γ = 5/3 for a monoatomic gas. P₂ = P₁(V₁/V₂)^γ = P₁ × 8^(5/3) = P₁ × 2⁵ = 32P₁. 64P₁ would correspond to γ = 2, and 16P₁ to γ = 4/3. Answer (4).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.