Q. The IUPAC name of the compound CH₃CH=CHC≡CH is
A) Pent-4-yn-2-ene
B) Pent-3-en-1-yne
C) Pent-2-en-4-yne
D) Pent-1-yn-3-ene
Explanation
[Solution from source] Number the chain so the multiple bonds get the lowest locants: from the C≡CH end the triple bond is at C-1 and the double bond at C-3, giving pent-3-en-1-yne. Numbering from the CH₃ end gives the higher set {2,4}, so pent-2-en-4-yne is wrong. Answer (2).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.