Q. In the following reaction: C₆H₅CH₂Br —(1. Mg, ether; 2. H₃O⁺)→ X the product 'X' is
A) C₆H₅CH₂OCH₂C₆H₅
B) C₆H₅CH₂OH
C) C₆H₅CH₃
D) C₆H₅CH₂CH₂C₆H₅
Explanation
[Solution from source] Benzyl bromide with Mg in dry ether forms the Grignard reagent C₆H₅CH₂MgBr, and hydrolysis with H₃O⁺ replaces MgBr by H, giving toluene C₆H₅CH₃. Benzyl alcohol would need reaction with O₂ or formaldehyde, not plain hydrolysis; bibenzyl is a Wurtz-type side product. Answer (3).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.