Q. A particle moves a distance x in time t according to equation x = (t + 5)⁻¹. The acceleration of particle is proportional to
A) (Velocity)²ᐟ³
B) (Velocity)³ᐟ²
C) (Distance)²
D) (Distance)⁻²
Explanation
[Solution from source] With x = (t + 5)⁻¹, v = −(t + 5)⁻² and a = 2(t + 5)⁻³. Since |v| = (t + 5)⁻², (t + 5)⁻³ = |v|^(3/2), so a ∝ (velocity)^(3/2). In terms of distance a = 2x³, so neither (distance)² nor (distance)⁻² fits. Answer (2).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.